4x(3x\Xb2-2x+3)-63x-X(2x-5)
4x(3x²-2x+3)-63x-x(2x-5)
4x(3x²−2x+3)−6(3x−x(2x−5))
Distribute:--->
=(4x)(3x²)+(4x)(−2x)+(4x)(3)+(−6)(3x)+(−6)(−2x²+5x)
=12x³−8x²+12x−18x+12x²−30x
=(12x³)+(−8x²+12x²)+(12x−18x−30x)
=12x³+4x²−36x
Answer:
=12x³+4x²−36x
#JuneChallenge
Comments
Post a Comment